C Logic & Problem Solving

Problem Proclamation
You will be offered some sort of 66 second selection. A great hourglass within a selection can be a percentage molded this way:
some sort of m j debbie i f ree p grams
For instance, when people generate a great hourglass with the phone number 1 in a selection filled with zeros, it might just are similar to the following:
1 1 1 0 0 0 0 1 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Really there are plenty of hourglasses inside selection previously mentioned. That a few leftmost hourglasses are definitely the next:
1 1 1 1 1 0 1 0 0 1 0 0 1 1 1 1 1 0 1 0 0
The sum of the a great hourglass is usually the sum of the most of the results inside the idea. That amount for any hourglasses previously mentioned are generally 7, several, together with two, respectively.
From this issue you must create the main amount with most of the hourglasses inside selection.
Take note:  If you've got now sorted the challenge Espresso second selection inside info buildings page inside Espresso sector, it's possible you'll pass by the following test.
Feedback Framework
You will have just 6 marks, just about every that contain 6 integers seperated just by rooms. Just about every integer are going to be concerning -9 together with 9 comprehensive.
Productivity Framework
Create the result to the current issue using one sections.
Test Feedback
1 1 1 0 0 0 0 1 0 0 0 0 1 1 1 0 0 0 0 0 two several several 0 0 0 0 two 0 0 0 0 1 two several 0
Test Productivity
two several several two 1 two several
Issue Connection:  -array
Answer:
#include<bits/stdc++. h> applying namespace a sexually transmitted disease; and Prosen Ghosh North american World University or college : Bangladesh (AIUB) and int main() int ar1010, maxSum = -36985247; for(int as i = 0; as i < 6; i++) for(int m = 0; m < 6; j++)cin >> arij; for(int as i = 0; as i < 6; i++) for(int m = 0; m < 6; j++) if(j+2 < 6 && i+2 < 6 ) int amount = arij + arij+1 + arij+2 + ari+1j+1 + ari+2j + ari+2j+1 + ari+2j+2; if(sum > maxSum)maxSum = amount; cout << maxSum << endl; profit 0;
Released just by
Ex boyfriend or girlfriend:
Precisely what is a productivity?
it ought to be -63 that's higher than -36985247(a non-selected poor value) therefore, the end result are going to be -63. additionally arranged any sort of good sized poor benefits, that's higher than and add up to -63.
Issue Proclamation
You will be offered some sort of 66 second selection. A great hourglass within a selection can be a percentage molded this way:
some sort of m j debbie i f ree p grams
For instance, when people generate a great hourglass with the phone number 1 in a selection filled with zeros, it might just are similar to the following:
1 1 1 0 0 0 0 1 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Really there are plenty of hourglasses inside selection previously mentioned. That a few leftmost hourglasses are definitely the next:
1 1 1 1 1 0 1 0 0 1 0 0 1 1 1 1 1 0 1 0 0
The sum of the a great hourglass is usually the sum of the most of the results inside the idea. That amount for any hourglasses previously mentioned are generally 7, several, together with two, respectively.
From this issue you must create the main amount with most of the hourglasses inside selection.
Take note:  If you've got now sorted the challenge Espresso second selection inside info buildings page inside Espresso sector, it's possible you'll pass by the following test.
Feedback Framework
You will have just 6 marks, just about every that contain 6 integers seperated just by rooms. Just about every integer are going to be concerning -9 together with 9 comprehensive.
Productivity Framework
Create the result to the current issue using one sections.
Test Feedback
1 1 1 0 0 0 0 1 0 0 0 0 1 1 1 0 0 0 0 0 two several several 0 0 0 0 two 0 0 0 0 1 two several 0
Test Productivity
two several several two 1 two several
Issue Connection:  -array
Answer:
#include<bits/stdc++. h> applying namespace a sexually transmitted disease; and Prosen Ghosh North american World University or college : Bangladesh (AIUB) and int main() int ar1010, maxSum = -36985247; for(int as i = 0; as i < 6; i++) for(int m = 0; m < 6; j++)cin >> arij; for(int as i = 0; as i < 6; i++) for(int m = 0; m < 6; j++) if(j+2 < 6 && i+2 < 6 ) int amount = arij + arij+1 + arij+2 + ari+1j+1 + ari+2j + ari+2j+1 + ari+2j+2; if(sum > maxSum)maxSum = amount; cout << maxSum << endl; profit 0;
Released just by
Ex boyfriend or girlfriend:
Precisely what is a productivity?
it ought to be -63 that's higher than -36985247(a non-selected poor value) therefore, the end result are going to be -63. additionally arranged any sort of good sized poor benefits, that's higher than and add up to -63.